Recent content by usermanual

how do you know if a reaction will take place or not like i know that i have to use the activity series and all but isn't that only when the reaction thing is single displacement where there 1 element in the first thing and then 2 element in the second compound so like this (a+ bc= ac + b) so...

cuz ehild i was thinking that for x^2-36x+288=0 since a=1 b=-36 c=288 so don't that mean that i have to find 2 values that add to equal -36 and multiply to give us 288?

ehild thanks you so much i get everything except for 1 thing . you know for that answer right for x=12and x=24 because 12+24 doesn't equal -36 shouldn't it be x= -12 and x=-24 because -12*-24= 288 and -12 + (-24)= -36 but if this is the case, then why would the distance be negative. i...

actually E.Hild i have 1 last question. you know for that answer right for x=12and x=24 because 12+24 don't equal -36 shouldn't it be x= -12 and x=-24 because -12*-24= 288 and -12 + (-24)= -36 but if this is the case, then why would the distance be negative.

ehild how would i cross multiply when there is an addition sign \frac{1}{x}+\frac{1}{36-x} isn't it true that i can't break up this up i tired the quadratic form " x2 -36x -8 =0 just wondering if this is the correct quadratic form. srry i kno I am being a nuisance

ok so "Do" is from the candle to the lens and "Di" is from the lens to the screen

um E. Hild i have drawn the picture and i still don't get it =( candle _____________________________________screen <----------------------------> 36cm btw is this a trick question, or does it have something to do with the word "sharp" in the...

ehild thanks for the quick reply btw you kno how you ended your post with "ehild" lol i thought you were calling me a child lmao ok but on topic ehild would i do 36cm divdied by 2 so 18 and then i just plug in 18 as the value of do O.O cuz when i did that i got 14.4 as the value of di...

Homework Statement a candle is placed 36cm from a screen. where between the candle and the screen should a converging lens with a focal length of 8.0cm be placed to produce a sharp image on the screen? Homework Equations 1/focal length = 1/distance of object from lens + 1/distance of...