roof angle as wedge
could i some how use the wedge where 2 sloping rooftops come together as a wedge?
if you are looking down onto the roof from straight overhead the roof is a U shape and each of the three slopes towards the center, so as if you were looking into an upside down hollow...
first, this is for my actual home's rooftop and isn't school related. I am not in a physics class.
i have 2 areas of 10'X20' of gutters filled halfway with water on my inclined roof. the gutters are 10 feet long and have a radius of 2inches. each gutter is evenly placed one foot apart from...
ok i found the distance from top of incline to bottom of incline to be .459meters using laws of triangles. so if friction is acting the velocity is gsin33-.19gcos33 and that equals 3.7758
v2=2ad
v2=3.466
v=1.8618
ok so we got Vi at the bottom to be 1.861 and the y1 and y2 at the bottom...
3.4kg rock starts at 25 cm on a plane with a 33degree angle. upon reaching the bottom the box slides along the horizontal. friction coeff is
.19. how far does the box slide on the horizontal before coming to a rest?
ok i need to use .5MVi2 + MGy1 = .5MVf2 + MGy2 + Ffrd
first i need to...
the angle is on the horizontal. i think i need to use forumla V2y=V2oy-2gdeltay? nevermind on my answer about Vy...Im stumped
edit..
ok Vfy2=0+2(9.8)(1.14)
Vfy=4.726 m/s
the angle is on the horizontal. nevermind on that Vy answer. I am stumped. how do i find Vxo and Vyo? is Y just the difference in the goal height and the height from which he shot? so Y is 1.14? and x is 10m?
a basketball player is 1.9m tall, wants to make a basket 10m away. the basket is 3.05m tall. gravity is 9.8, if he shoots from a height of 1.91m at 33.3 degree angle, what initial speed is thrown to make a basket?
i have no clue how to find initial velocity when it isn't given.