Thanks for the quick response, I think I see where to go from here, but just to make sure.
Let \delta = \epsilon^{2}
We know \left| y + y_{0} \right| > \left| y - y_{0} \right| since y and y_{0} are positive.
and since \left| y + y_{0} \right| \left| y - y_{0} \right| < \delta = \epsilon^{2}...
Homework Statement
This is a problem from my Analysis exam review sheet.
Let L(x) = \sqrt{x}. Prove L is continuous on E = (0,\infty)
The Attempt at a Solution
The way we've been doing these proofs all semester is to let \epsilon > 0 be given, then assume \left| x -x_{0} \right| <...