Recent content by Vahn

I see. So, assuming C = (0,0), A = (1, 0), B = (1, 1), I have: BM: y_{BM} = 2 x_{BM} - 1 AP: y_{AP} = \frac{- x_{AP} + 1}{2} BC: y_{BC} = x_{BC} So P = (\frac{1}{3}, \frac{1}{3}) and BP:PC=2:1, which is the correct answer :). However, the 'official' resolution of this problem is the...

Homework Statement Let \bigtriangleup ABC be a right angled triangle such that \angle A = 90°, AB = AC and let M be the midpoint of the side AC. Take the point P on the side BC so that AP is vertical to BM. Let H be the intersection point of AP and BM. Find the ratio BP:PC. Homework Equations...