Any suggestions about expanding
(1+ax)^3/2
for 5 non-zero terms?
using pascal's triangle I am gettin horrible exponents while if i rewrite it as (Root of [1+ax])^3 it doesn't look much better as i don't have two clear values to use in the formula :\
yup using the change of base i got to: ln x/ln 81 + ln3/lnx = 2 but that's as far as i got. I tried simplifying them, getting a common denominator, bringing onto the other side but seems nothing that i do gets me to a solution
The equation is the following:
Log81x + logx3 = 2
I've been bashing my head with change of base but i can't seem to get anywhere with it. 81 is rewritable as 34 which seems like it has something to do with the solution, but i just can't seem to get the hang of it. I always get stuck with...