Recent content by Vash
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Evaluating the Integral of (arcsinx)^2dx using Integration by Parts
Im not sure how to do it your way so I just set it up by integration by parts. u=arcsinx, du=1/(sqrt(1-x^2)) dv=dx v=x. When I do it i get my answer above.- Vash
- Post #7
- Forum: Calculus and Beyond Homework Help
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Evaluating the Integral of (arcsinx)^2dx using Integration by Parts
im getting xarcsinx+sqrt(1-x^2)- Vash
- Post #5
- Forum: Calculus and Beyond Homework Help
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Evaluating the Integral of (arcsinx)^2dx using Integration by Parts
That's what I've been doing and it still doesn't work out for me...oh well, I'll keep trying.- Vash
- Post #3
- Forum: Calculus and Beyond Homework Help
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Evaluating the Integral of (arcsinx)^2dx using Integration by Parts
Homework Statement elvaluate this integral (arcsinx)^2dx Homework Equations (arcsinx)^2dx The Attempt at a Solution integration by parts, let u= arcsinx and make y=arcsinx for easier integration. Once i plug it into the parts equation it turns into a mess. Any help would be superb.- Vash
- Thread
- Integral
- Replies: 7
- Forum: Calculus and Beyond Homework Help
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1st year engineering physics problem
thanks :)- Vash
- Post #9
- Forum: Introductory Physics Homework Help
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1st year engineering physics problem
ok i figured it out, thanks for your replies.- Vash
- Post #7
- Forum: Introductory Physics Homework Help
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1st year engineering physics problem
Yes that is true, I am just waiting on someone to check if my equations are correct.- Vash
- Post #5
- Forum: Introductory Physics Homework Help
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1st year engineering physics problem
my equations are: s1=1/2at1^2 v1=at1 1000m=s1+v1(t2-t1)+1/2a(t2-t1)^2 v2=0=v1+a(t2-t1) Those are my equations...I think i know what to do, but setting it up is the problem. Before I move on, do they seem correct?- Vash
- Post #3
- Forum: Introductory Physics Homework Help
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1st year engineering physics problem
Im having troubles with this question for my assignment... Determine the time required for a car to travel 1km along a road if the car starts from rest, reaches a max speed at some intermediate point, and then stops at the end of the road. The car can accelerate at 1.5 m/s^2 and decelerate at...- Vash
- Thread
- Engineering Engineering physics Physics Year
- Replies: 8
- Forum: Introductory Physics Homework Help