Recent content by Victor8108

Ok, according to the fundamental theorem of calculus: if g(x)= f(t)dt from a to x, then g'(x)=f(x) applying this to my problem, then it becomes g'(x)= sqrt(1-x^9)-sqrt(1-x^6)

For those wondering why the equation f(x,y) has no y, here is the complete function: f(x,y)= (x^2)y+integral of sqrt(1-t^3)dt from x^2 to x^3. I figured the first part(x^2)y so I didnt put it in the equation. sorry about the inconvenience.

Figured I should probably post this in the homework section. Sorry about that.

Homework Statement Find df/dx, f(x,y)=integral of sqrt(1-t^3)dt from x^2 to x^3. Since it is asking to find the derivative with respect to x,should I regard t as a constant? Homework Equations The Attempt at a Solution I tried to find the antiderivative of the integral...

Hi all, I'm trying to figure out the following problem: Find df/dx, f(x,y)=integral of sqrt(1-t^3)dt from x^2 to x^3. Since it is asking to find the derivative with respect to x,should I regard t as a constant?