Recent content by wais

How could I calculate the amount of heat needed to apply to make kevlar react? I know its 500c but I just want to add into my presentation the calculation used. Thanks.

Hey, I know this is my 3rd topic on kevlar but they arent the same question so :P Anyway, DuPont (the company who own the Kevlar brand) claim that it is flexible, yet it is a cristaline ploymer which makes it stiff, so how can it be flexible as well? Thanks.

Hi, I found out that Kevlar is a crystalline structured polymer, and this is one of the factors about why its so strong. Could someone explain to me why crystallinity affects strenght? Thanks.

Ah great thanks. I also saw that kevlar has a "self extinguishing" property, could you tell me how this would work?

Hey, I'm doing a presentation on Kevlar, and was asked to state its properties and why it has those. I came across the fact that kevlar has a low flamability due to the high carbon:hydrogen ratio, I'm assuming that carbon doesn't burn whereas hydrogen does. Am i correct? Sorry it may be a bit...

Yes, the correct answer is b. A local max/min is a point on a graph that is the highest or lowest point in a specific interval, while a relative max/min is a point on a graph that is the highest or lowest point in the entire function.

Therefore, the width of the box is approximately 108 picometers. This calculation assumes a one-dimensional box, as the question does not specify the dimensions of the box. If the box is two or three-dimensional, the calculation would change accordingly.

: Hi there, It sounds like you have been working on this problem for a while and are feeling frustrated. Don't worry, it's common to get stuck on problems in optics. First, let's break down the problem and see if we can approach it in a different way. The question is asking for the diameter...

To find the second derivative, we can use the Quotient Rule again, but it would be easier to simplify the first derivative first. Let's start by rewriting the first derivative as: \frac {2y-x^2}{y^2-2x} = \frac {2y-x^2}{y^2-2x} \cdot \frac {1}{1} = \frac {2y-x^2}{y^2-2x} \cdot \frac...

for reaching out! To find the image and magnification in this scenario, we can use the equation: M = -v/u, where M is the magnification, v is the image distance, and u is the object distance. In this case, the object distance is equal to the focal length, so u = 8.0 cm. We want the image to be...

I completely understand your frustration with your recent physics test. It can be overwhelming when the time limit is too short and you feel rushed to recall formulas instead of understanding the concepts. It's great that you want to improve and find resources to help you practice and understand...

Hi there, The hint is suggesting that you approach the problem by considering the two electrodes as whole spheres immersed in a conducting medium, rather than just hemispheres pressed into the ground. This is because the flat surfaces of the electrodes are flush with the Earth's surface, and...

1. To calculate the speed of the car, we can use the formula speed = distance/time. Since the distance is given in miles and the time in minutes, we need to make sure to convert the units to be consistent. We can convert 5 miles to 8.05 kilometers (since 1 mile = 1.609 kilometers) and 5.5...

There are a few potential sources of error in your calculation. Firstly, the expression for dq should be dq = eta * dL, since dA is equal to R * dL for a cylindrical shell. Secondly, the integral should be taken over the entire length of the cylinder, not just a small portion of it...

Yes, it is possible to have a naturally occurring situation where an object is being acted upon by only a single force. One example of this is a satellite in orbit around the Earth. The only force acting on the satellite is the force of gravity from the Earth. This is because the satellite is in...