Recent content by waldvocm

opps! W=9481J Final answer! Was I correct in choosing W=Kf-Ki for my equation in this problem?

A truck carrying a 65.4kg crate accelerates from rest to 61.3km/hr on a flat horizontal surface in 15.2s The acceleration was not constant. HOw much work was done on the crate by the truck? W=Kf-Ki W=(1/2*65.4kg*220680000^2)-0 W=1.59e18 Is this correct?

Ok, that answer was wrong. Does anyone have any suggestions?

I found that R=16 I did this just by looking at the picture. Ro=32 and it looks like the plumb bob is about half of that to the right. So, I found the angle to be 13.7 degrees T=mg/cos(13.7) T=201.7 The difference in T=5.80N Does this look right?

Can anyone help on this one?

F=100a Fs=.553ma Fs>F The force that needs to be supplied by static friction is m's weight mg=98 98=.553N N=177.2 So the minimum force must be 177.2N and the acceleration is F=ma 177.2=(M+m)a 177.2=(110)a a=1.61 Is this correct? :)

Calculate the increase in tension in the string holding up the bob in the rotating chair. Calculate the tension when the bob is hanging vertically and the tension when the chair is rotating. H=65.3cm Ro=32cm The bob is 20.0g I found that the Tension in the string when the bob is hanging...

The Normal Force is mg (of the large block)+coefficient of static friction? So is the Normal force the same as the applied force in this situation?

So... F=m*v^2/r 9.80=m*23.8^2/r How do I solve for r if I don't know the mass of the package?

An automobile moves at a constant speed over the crest of a hill traveling at a speed of 85.7km.h. At the top of the hill a package on a seat in the rear of the car barely remains in contact with the seat. What is the radius of curvature (m) of the hill? 85.7km/h=2.38m.s v=2.38m/s...

When you say M2, I am assuming you mean m (the little block that is suspended). So, to find the minimum force F that must be exerted on M (the big block) for m not to fall is; The weight of m (the small block) times the coefficient of static friction? Fs=.553*98=54.194 So that is the force...

To find the acceleration I take Fapplied=(M+m)a To find Fapplied I take F-s*N=M+m

I am still confused. Here is my problem: In the figure shown, the coefficients of friction between the two blocks are s=0.553 and k=0.336 There is no friction on the horizontal surfaces. a) What is the minimum force F(N) must be exerted on the block M in order for the block m to not fall...

The acceleration is supposed to be -.78. I am getting .78. That is what you got too?

Ok, I really struggle solving these equations I solved one of the equations for T T=Ma+Mg and put this in the other equation for T mg-(Ma+Mg)=ma 80.36-(15.7a+153.86)=8.2a 80.36+153.86=8.2a+15.7a a=9.8 What am I missing here?