:P Right. I missed that you had canceled the C in the denominator.
Ahhhh! The quadratic Eq'n! Forgot about that old chestnut. Alright, let's give this a try.
C=\frac{-\left(\frac{\pi(D+d)}{2}-L\right)\pm \sqrt{\left(\frac{\pi(D+d)}{2}\right)^2-4(2)\left(\frac{(D-d)^2}{4}\right)}}{2(2)}...
Ok, So I'm guessing
L = 2C+\frac{\pi(D+d)}{2}+\frac{(D-d)^{2}}{4C}
Should become
LC = 2C^2+\frac{\pi C(D+d)}{2}+\frac{C(D-d)^{2}}{4C}
Is that correct?
It still has me wondering why the C doesn't effect the denominator.
Ok, looking good so far, but how come the second part (D-d)^2/4 isn't also multiplied by C and why are the denominators not multiplied by C?
Ugh, I also suck at factoring. I need to go through my algebra textbook again and teach myself all this stuff from scratch.
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