Recent content by wannabe92

Let X1 be a binomial random variable with n1 trials and p1 = 0.2 and X2 be an independent binomial random variable with n2 trials and p2 = 0.8. Find the probability function of Y = X1 + n2 – X2. Exactly how does one calculate the mgf of (n2 - X2)?

Is it 1/(1-2s) . 1/(1-3t)?

Hi, I've no idea where to go with the question below: Joint moment generating function of X and Y - MXY(s,t) = 1/(1-2s-3t+6st) for s<1/2, t<1/3. Find P(min(X,Y) > 0.95) and P(max(X,Y) > 0.8)

So is this how it goes, based on the given values of x and P(X=x): P(|X-2.31| >= 1.074) = P( X-2.31 >= 1.074) + P( 2.31-X >= 1.074) = P( X >= 3.384) + P( X <= 1.236) = 0.16 + 0.19 + 0.04 = 0.39

I only managed this much: Expected value = 2.31 Standard deviation = 1.074 P( |X - 2.31| >= 1.074) =P( -1.074 >= (X - 2.31) >= 1.074 ) =P( 1.236 >= X >= 3.384) I'm stuck here. For question b, I assume I have to calculate the expected value of C by substituting the variables x and x^2...

The following table gives the probability distribution of X, the number of defective products in a production line in a day. x P(X=x) 0 0.04 1 0.19 2 0.35 3 0.26 4 0.16 a. Evaluate P(|X - expected value| >= standard dev) b. The...

I'm using the mgf of exponential: lambda/(lambda -t). So, to obtain the probability, simply integrate the probability density function of X with the values of a1 and b1, is that it?

From the pdf of X, f(x) = 1/8 e^-x/8, x > 0, find the mgf of Y=X/4 +1. What is then the value of P(2.3 < Y < 4.1)? Homework Statement Homework Equations Moment generating function of exponential distributionThe Attempt at a Solution I have the mgf of X, which is 1/8 / (1/8 - t). I have also...