Recent content by waofy

Yes, you're right, that is exactly how the Lyapunov exponent is defined. The reason why it's not usually calculated this way is because the exponent only defines local behaviour for bounded systems (i.e. ones that come back on themselves to form cycles). If the divergence due to the Lyapunov...

That value does seem far too large, unless the typical frequency of the oscillations are in the 100kHz range. The Lyapunov exponent just tells you the rate at which two close trajectories diverge (e.g. two simulations of the pendulum with slightly different initial conditions). Due to the...

Thanks, that makes more sense. I think it is still true that in dissipative systems the sum of the Lyapunov exponents is negative though (http://books.google.co.uk/books?id=Uqc7zC7NULMC&pg=PA212&lpg=PA212#v=onepage&q&f=false" - first line). It makes sense that the overall exponent for the...

Hi, the discussions in this forum have always been a great help to me as it seems there's always someone who's answered my question. However, this time I'm still puzzled. People often talk about the sum of the Lyapunov exponents of a dynamical system (i.e. adding the exponents from each...