Ok your expressions and mine are same. But that means I still get different results than I am supposed to get.
For instance, when i simulate the circuit, i find the i2 = 5.5A
But in our equations, 13/5=2.6
You can solve them here:
http://www.numberempire.com/equationsolver.php
in this...
So i found the following equations:
eq1=((-6*(((12*i2)+i3)-i2)) + (4*i2) + (2*(i2-i3)));
eq2=((-10) + 2*(i3-i2) + vx );
eq3=((2*((((12*i2)+i3))-(8))) + (-vx) + (4*(((12*i2)+i3))));
When i solve it with matlab, the results are:
solutions_i2 = 13/5
solutions_i3 = -39/2...
If I got what you are saying, then loop 3 equations is:
-10 + 2(I3-I2) + Vx = 0
and loop 4 is:
2(I4-I1) - Vx + 4I4 = 0
correct?
But how do i find the Vx?
Homework Statement
Homework Equations
V=I*R
The Attempt at a Solution
I started writing the equations for each loop.
Loop 1 -> I1=8A
Loop 2 -> -6Ix + 4I2 + 2(I2-I3) =0 and Ix=I4-I2
Loop 3 -> I don't know how to approach the dependent current source here.
Loop 4...