Recent content by warden13

Ok your expressions and mine are same. But that means I still get different results than I am supposed to get. For instance, when i simulate the circuit, i find the i2 = 5.5A But in our equations, 13/5=2.6 You can solve them here: http://www.numberempire.com/equationsolver.php in this...

So i found the following equations: eq1=((-6*(((12*i2)+i3)-i2)) + (4*i2) + (2*(i2-i3))); eq2=((-10) + 2*(i3-i2) + vx ); eq3=((2*((((12*i2)+i3))-(8))) + (-vx) + (4*(((12*i2)+i3)))); When i solve it with matlab, the results are: solutions_i2 = 13/5 solutions_i3 = -39/2...

I couldn't replace I4, can you tell me how to replace it?

If I got what you are saying, then loop 3 equations is: -10 + 2(I3-I2) + Vx = 0 and loop 4 is: 2(I4-I1) - Vx + 4I4 = 0 correct? But how do i find the Vx?

Homework Statement Homework Equations V=I*R The Attempt at a Solution I started writing the equations for each loop. Loop 1 -> I1=8A Loop 2 -> -6Ix + 4I2 + 2(I2-I3) =0 and Ix=I4-I2 Loop 3 -> I don't know how to approach the dependent current source here. Loop 4...