Recent content by warrior_1

But is there a quantum physics explanation for this. As this is for a physics course, and they don't really go into how many electrons fill a shell etc, i understand what ur talking about coz I've done chem b4 but this is for a quantum mechanics course.

But u can see in that figure, once u add an extra electron after the shell is filled it automatically drops off right, once u add the second the ionization energy increases, once you add the third it drops off again... i obviously don't understand what's going on here so by no means am i saying...

Is the reason why the energy liberating fustion process ends with uranium(more precisely Iron) is that uranium's bindind energy per nucleon begins to decrease and hence will absorb energy rather than emit it, and thus is not self sustaining? Thanks in Advance

Hi with respect to the bremsstralung and the Xray emission, i have a graph of the xray emmision and at the end of the bremsstrahlung, at roughly 35 KeV,there is a sharp cut off. Is the reason for this because that 35KeV is the maximum energy of the incident electrons, and hence no photon...

This question is not a homework question. I am having a little trouble with the ionization energy graph. I understand that the noble gasses are the most stable and hence require the most energy to be ionised, but why is it that after you add even number of electrons the ionization energy...

Im really having troubles understanding the divergence form of gauss's law. I have done research on it and am still not able to understand it. it sates that E=\rho/\epsilon or E=rho/epslom, so does that mean that the upside down triangle has no significance, ie does that mean i can simply solve...

Oh yh. So the charge density is simply equal to epslom multiplied by the electric field?? So is this the only way to approach this qs.

*bump*

how do you use the differential form of gauss's law. So integral of E.da=qin/empslom if we differentiate both sides we get E= dq/da*(1/epslom)... so we have determined dq/da, which is equal to E*epslom, but how does that allow you to determine the charge density... because wouldn't charge...

Homework Statement Hi guys, i need a bit of help with the following question. Ok the question states the following, explain why the element of charge, dq, located within an infinitesimally thin spherical shell or radius r is equal to rho(r)*4*pi*(r)^2dr, where dr is the thickness of the...