Recent content by WesleyPipes

Well, I think I have given you too many free answers haha. Just use Ohm's law and you can figure out the input impedance. I = V/R. To get 0 current, your R must be ? Then you would have the same voltage on the other input if it is directly connected, they are always the same.

The current going into each input = 0 and the voltage is the same at each input. It's true for inverting and non-inverting.

The voltage at each of the op-amp's inputs is = V1. It's just a fact about ideal op-amps.

Node 4: (Vx4-5)/10K + (Vx4-Vx3)/10K + (Vx4-Vx2)/470R + (Vx4-Vx2)/1K = 0 Should be right for that node.

You're not forced to use a matrix to solve. Just solve your first two equations for different unknowns and substitute into the third.

Thanks, knew I was missing something simple. I feel a lot better now haha.

Why not use a 1V or 1A test source?

Do a KCL at Nodes 1-4. Hah...just read it and saw you did already I think. But as an example at Node 1... (Vx1-10)/R1 + (Vx1-Vx3)/10K + (Vx1-Vx2)/1K = 0 I think in your KCLs you worked backwards compared to me so not sure if this will help or confuse you.

Well, I am raging over my homework and not even going to turn it in because I can't complete enough of it. I really just need to figure this problem out so I don't feel as bad about it. I know this shouldn't be as hard as I am making it, but all examples only have answers containing a...