Recent content by WhackyWookie

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    Solving Resonance Problem: Explain Frequency of Tuning Fork

    Chen, I went to the link, but their solution makes no sense. They assumed that the 0.125m and 0.395m tubes' resonant frequency differs by 1 harmonics and used nothing to back that up. Additionally, as I have said before, 635 hz is below the fundamental frequency of a 0.125 m half open tube...
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    Solving Flotation Problem: Estimate a Polar Bear's Mass

    thnx for ur explanation, but the answer I got using ur method is the same as I got before (592.9 kg), which is inconsistent with the 790 kg answer listed on the back of the book.
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    Solving Resonance Problem: Explain Frequency of Tuning Fork

    A tuning fork is set into vibration above a vertica oepn tube filled with water. The water level is allowed to drop slowly. As it does, the air in the tube above the water level is heard to resonate with the tuning fork when the distance from the tube opening to the water level is 0.125 m and...
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    Solving Flotation Problem: Estimate a Polar Bear's Mass

    The problem is: A polar bear partially supports herself by pulling part of her body out of the water onto a rectangular slab of ice. The ice (with specific gravity of 0.917) sinks down so that only half of what was once exposed now is exposed, and the bear has 70% of her volume and weight out...
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    Rotational Freefall and Designation of Axis

    I understand arildno's explanation for the 2nd question. can't believe i overlooked that. But the rest I'm still somewhat vague about. can you guys elaborate a bit more in context to this question: If one was to impart a force on the end of a pen in space at 90 degree, would the pen move...
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    Rotational Freefall and Designation of Axis

    Well, I'm not even sure if freefall is the right word, but my first quandary is as followed: If two objects fall from the same height, and one object will begin to rotate after it has been release (ie. a yoyo), while the other will not rotate, then the rotating object will accelerate slower...
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