Oh a = v2/r
I think I get it now.
So there is no upward force at all? Can you explain how that works? My teacher was talking about it in class but since it's new I don't understand it all yet
Well the acceleration is straight down since the car is at the top of the hill. So that would then add to Fg and make it larger (not the actual force of gravity, it would just be Fg + a).
I feel like I should simply make Fg negative but I don't understand why.
Ah wait. There is a second question that is really similar. Instead of being in a valley the car is on top of a hill.
m = 1200 kg
r = 25 meters
speed = 43 km/hr = 11.94 m/s
Does that original formula change? The first question was Fn - Fg = (mv2)/r
However, when I used this equation my...
Wow that was really simple...sorry sometimes even the simplest stuff in physics just goes over my head. Thank you, especially for my equation corrections!
So Fn = 41,760 N
Homework Statement
A car is traveling through a valley at a constant speed, though not a constant velocity and (I believe) it is at the bottom. If the car's speed is 25 m/s, its mass is 1200 kg and the radius of the valley (r) is 25 meters, Use your force diagram to create a Fnet=ma equation...