Nevermind, i got it all figured out. the zeros of the first derivative give you the maxs and mins and you just plug back in. apparently i can't remember calc 1 anymore. whoops. but thank you for your help!
I forgot to graph in radians. i switched modes and got a curve with maximums at t=0, pi, and 2 pi. minimums at pi/2 and 3pi/2. how do i find which is the actual max and min if I'm given just the parametric? do i need the second derivative? for the second derivative i got -8sint*cost +...
Ok nevermind, i just graphed in degrees instead of radians. it's been a long week, obviously :( ok, i think i know what I'm doing now. sorry for the confusion :P
Ok, this is what i have
dT/dt= ∂T/∂x (dx/dt) + ∂T/∂y (dy/dt)
=y(-2sqrt2 sint(t)) + x(sqrt 2 cos(t))
then plug in y and x from the given and i got...
(-4sint*sint) + (4 cost*cost)
when i graphed that, i got a straight line at 4.
Where did i go wrong?
Homework Statement
Let T= g(x,y) be the temperature at the point (x,y) on the ellipse x=2sqrt2 cos(t) and y= sqrt2 sin(t), t is from 0 to 2pi. suppose that partial derivative of T with respect to x is equal to y and partial derivative of T with respect to y is equal to x. Locate the max and...
Alright, thanks! i think i got my answer. i ended up getting an acceleration vector of 11sqrt2 i + 7sqrt2 j. now i just need to multiply that by the mass to get the vector of the force. do i need to convert pounds to slugs? then my total force will be in pounds?
Homework Statement
In the xy plane, where distances are measured in feet, a 96 lb object is moving from left to right on the curve y=e^-x. At t-0 its speed is 6ft/s and is speeding up at (square root of 8) ft/s^2. what is the total force on it at that point? Give floating point values for...