Recent content by willybirkin

Wow, I can't believe I missed that. Well then, after some manipulation that equation ought to become r\sqrt{2}ei\sqrt{2}(\theta+2k\pi) which unless I'm mistaken shouldn't ever be able to return to the original \theta, making it infinitely valued.

The positive and negative square roots of 2. Or, if you consider 2 to be complex with imaginary part 0 and real part 2, root(2)eik\pi with k=0,1.

Homework Statement For z complex: a.) is z\sqrt{2} a multi-valued function, if so how many values does it have? b.) Claim: z\sqrt{2}=e\sqrt{2}ln(z)=e\sqrt{2}eln(z)=ze\sqrt{2} Since \sqrt{2} has 2 values, z\sqrt{2} is 2 valued. Is this correct? If not, correct it. Homework...