Recent content by wilson_chem90
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Using Coulombs Law-Comparative Analysis
Homework Statement Look back at the Example in the Using Coulombs Law-Comparative Analysis section. Calculate the magnitude of F2 if both changes occurred simultaneously-that is, if the distance between the charges doubled and the size of once tripled, while the size of the other doubled...- wilson_chem90
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- Analysis Coulombs
- Replies: 3
- Forum: Introductory Physics Homework Help
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Calculating F2 for Double and Triple Changes in Coulombs Law"
sorry i forgot to cancel r1, its actually F2 = 6F1/4- wilson_chem90
- Post #4
- Forum: Introductory Physics Homework Help
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Calculating F2 for Double and Triple Changes in Coulombs Law"
ohh okay, sorry i thought it mean't something else. Do i ended up setting F1/F2 = (q1q2/r1^2) / ((3q1)(2q1)/2r1^2) I rearranged it to be F2 = 6F1/4r1 (after cancellations and rearranging) Im not sure if i rearranged it correctly...- wilson_chem90
- Post #3
- Forum: Introductory Physics Homework Help
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How much TNT equals 1 gram of U-235 in energy?
nice! thank you for your help- wilson_chem90
- Post #8
- Forum: Introductory Physics Homework Help
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How much TNT equals 1 gram of U-235 in energy?
well for example, the question number is 70, and the nuclear reaction is part a, and this question is part b. So I'm guessing they're linked together. And once i find the other energy amount, i just divide it by the TNT energy level to find the amount of grams in TNT- wilson_chem90
- Post #6
- Forum: Introductory Physics Homework Help
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How much TNT equals 1 gram of U-235 in energy?
so what do i do with the nuclei? do i divide them by the amount of energy during the reaction?- wilson_chem90
- Post #4
- Forum: Introductory Physics Homework Help
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Distance to Moon from light travel time of 2.562 seconds
oh okay thank you very much- wilson_chem90
- Post #5
- Forum: Introductory Physics Homework Help
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Distance to Moon from light travel time of 2.562 seconds
so does that mean i divide it by 2?- wilson_chem90
- Post #3
- Forum: Introductory Physics Homework Help
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Distance to Moon from light travel time of 2.562 seconds
Homework Statement Mirrors left behind the Moon have been used to measure the distance between Earth and the Moon accurately. If the time required for a pulse of light to reach the Moon and return to Earth is 2.562 s, calculate the distance between Earth and the Moon in kilometers...- wilson_chem90
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- Space
- Replies: 4
- Forum: Introductory Physics Homework Help
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How much TNT equals 1 gram of U-235 in energy?
okay, well there was a question before this one that was linked to this one, and it involved a U-235 reaction and the answer for the energy released was 4.79 x 10^-10 J. would that be it?- wilson_chem90
- Post #3
- Forum: Introductory Physics Homework Help
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How much TNT equals 1 gram of U-235 in energy?
Homework Statement Nuclear energy changes are significantly greater than chemical changes. The detonation of 1.00 g of the explosive trinitrotoluene (TNT) releases 2.760 kJ. How many grams of TNT would be needed to match the energy released be one gram of U-235? (HINT: 1.00 g of U-235 contains...- wilson_chem90
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- Energy Nuclear Nuclear energy
- Replies: 7
- Forum: Introductory Physics Homework Help
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Calculating F2 for Double and Triple Changes in Coulombs Law"
Homework Statement Look back at the Example in the Using Coulombs Law-Comparative Analysis section. Calculate the magnitude of F2 if both changes occurred simultaneously-that is, if the distance between the charges doubled and the size of once tripled, while the size of the other doubled...- wilson_chem90
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- Coulombs Coulombs law Law
- Replies: 3
- Forum: Introductory Physics Homework Help
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Calculate Energy during Nuclear Fission
i couldn't do the laTeX image, but its 235/92 U + 1/0 n = 141/56 Ba + 92/63 Kr + 3 1/0 n- wilson_chem90
- Post #2
- Forum: Introductory Physics Homework Help
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Calculate Energy during Nuclear Fission
Homework Statement Another possible form of the fission of U-235 is: \begin{array}{cc}235&92\[\tex] U + \begin{array}{cc}1&0\[\tex] n [tex]/rightarrow [tex]\begin{array}{cc}141&56\[\tex] Ba + [tex]\begin{array}{cc}92&36\[\tex] Kr + 3 [tex]\begin{array}{cc}1&0\ n a) Given the masses of the...- wilson_chem90
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- Energy Fission Nuclear Nuclear fission
- Replies: 1
- Forum: Introductory Physics Homework Help