Recent content by Windwaker2004

thanks a lot for the reply! I realize JFETs aren't good compared to BJTs for voltage gain. I am just practicing different configurations, in this case 2 gain stages, and would like to know how to set up the circuit and get the equations. I do understand JFETs but need some help in this...

Hey guys, I am curious on how to set up a 2 stage JFET amplifier. I've reviewed some analysis on 2 stage BJT amplifiers as well as 2 stage BJT/JFET amplifiers but I cannot find anything on how to use 2 JFETs. Any help would be greatly appreciated. Thank you!

Thank you so much for your help. I made it a lot more complicated than that method. I worked it out and got the correct answer. Thanks again!

A cylindrical fishing reel has a moment of inertia of I=6.22×10-4 kg·m2 and a radius of 4.44 cm. A friction clutch in the reel exerts a restraining torque of 1.34 N·m if a fish pulls on the line. The fisherman gets a bite, and the reel begins to spin with an angular acceleration of 66.5 rad/s2...

Well, the \ sin45m is the component of the force of gravity acting parallel to the ramp. The only other component is perpendicular to the ramp which creates the friction. The component of the force parallel to the ramp is the only one that needs to be looked at for force applied (remember that...

*bump*...

There is a way to get the acceleration of the hamburger... Since \ F_a_p_p - F_f = ma and \ F_a_p_p = sin45(9.8m)\ and\ F_f = 0.597(9.8m) The applied force was found from the parallel component of the force of gravity acting on the hamburger. So... \ F_a_p_p\ - F_f = ma...

Hi, I need some help with this question: Find all values of \ k for which the lines do not intersect. \ (x-2,y+1,z-3) = (r,0,3r)\ and\ (x,y,z) = (2,1,4)\ +\ s(2,k,6) I put the first equation in vector form: \ (x,y,z) = (2,-1,3)\ +\ r(1,0,3) Now I know that if the direction...

Hi, I wanted to know if solid Iodine dissolves in hexane. I know they are both non-polar so they should dissolve atleast somewhat. The solution came out dark purple so doesn't that mean the Iodine dissolved in the hexane? Also is graphite polar or non polar? In my experiment it didn't dissolve...

Yes but if you don't assume the cord stretches, this must mean the poles give in a little or the cord just wouldn't budge. But like Doc said, I guess its more reasonable that the cord stretches before the poles move in.

Yea I agree. It makes sense now lol. OK thanks to the both of you!

I guess it is negligible because it is such a small difference.

True but if u calculate the hypotenuse using the sides 4 m and 0.08 m there is a little difference.

Ok thanks for straightening me out. But one last thing. You know how there is 8 m between the poles? Well this must mean that the rope is also 8 m because it is quite taut. But when it moves downwards the horizontal is still 4 m but why would the length of the clothesline (hypotenuse) change?

Alright thanks again!