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A problem on two dimensional kinematics
v(y0)=v(0)sin20°=5m/s×sin20°=1.71m/s since v(t)^2-v(y0)^2=2as,v(t)=0,a=-9.8m/s^2 h=v(y0)^2/2g=0.149 since a=(v(t)-v(0))/t ,t=v(t)-v(y0)/g=0.174s v(x0)=v(0)×cos20°=4.7m/s x=(v(xo)+v(t))×t/2=0.409m s=√[x^2+h^2]=0.435m That's what I've tried.- Winsy
- Post #5
- Forum: Introductory Physics Homework Help
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A problem on two dimensional kinematics
v(y0)=v(0)sin20°=5m/s×sin20°=1.71m/s since v(t)^2-v(y0)^2=2as,v(t)=0,a=-9.8m/s^2 h=v(y0)^2/2g=0.149 since a=(v(t)-v(0))/t ,t=v(t)-v(y0)/g=0.174s v(x0)=v(0)×cos20°=4.7m/s x=(v(xo)+v(t))×t/2=0.409m s=√[x^2+h^2]=0.435m That's what I've tried.- Winsy
- Post #4
- Forum: Introductory Physics Homework Help
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A problem on two dimensional kinematics
This is my attempts.- Winsy
- Post #2
- Forum: Introductory Physics Homework Help
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A problem on two dimensional kinematics
Homework Statement A block is given initial velocity of 5m/s up a frictionless 20 degrees incline. How far up the incline does the block slide before coming to rest? The answer is 3.73m. I set the coordinates to be perpendicular to the plane instead of parallel to the incline. I calculated...- Winsy
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- Kinematics
- Replies: 5
- Forum: Introductory Physics Homework Help