v(y0)=v(0)sin20°=5m/s×sin20°=1.71m/s
since v(t)^2-v(y0)^2=2as,v(t)=0,a=-9.8m/s^2
h=v(y0)^2/2g=0.149
since a=(v(t)-v(0))/t ,t=v(t)-v(y0)/g=0.174s
v(x0)=v(0)×cos20°=4.7m/s
x=(v(xo)+v(t))×t/2=0.409m
s=√[x^2+h^2]=0.435m
That's what I've tried.
v(y0)=v(0)sin20°=5m/s×sin20°=1.71m/s
since v(t)^2-v(y0)^2=2as,v(t)=0,a=-9.8m/s^2
h=v(y0)^2/2g=0.149
since a=(v(t)-v(0))/t ,t=v(t)-v(y0)/g=0.174s
v(x0)=v(0)×cos20°=4.7m/s
x=(v(xo)+v(t))×t/2=0.409m
s=√[x^2+h^2]=0.435m
That's what I've tried.
Homework Statement
A block is given initial velocity of 5m/s up a frictionless 20 degrees incline. How far up the incline does the block slide before coming to rest?
The answer is 3.73m.
I set the coordinates to be perpendicular to the plane instead of parallel to the incline. I calculated...