Recent content by wmrunner24

Okay. I think this was the missing link I needed. Let me make sure though: nHg = mHg/MHg, where MHg is the atomic mass of mercury, 200.59 g/mol nHg = 3.23 x 10-4 mol The number of moles of nitrogen can be calculated using the ideal gas law: nN2 = \frac{PV}{RT} = 0.718 mol, with P = 1...

Homework Statement At 1 atm of pressure a volume of 22 liters of N2 gas is passed in a closed system over a boat containing Hg liquid at 100°C. The flow of N2 is slow to allow the gas to become saturated with mercury. At 20°C and 1 atm, the nitrogen was found to contain 0.0647g of Hg...

We essentially have the same solution, because in the problem statement, k is given as 1/∏, so the ∏ and k multiply to unity (although there will of course be units left over from k). My constant of integration was the n term, just because C was in use so I picked another letter. Part 1 of...

Okay, I think I get it now. By separation of variables: \frac{Q}{A(x)}dx = -k dT = -1/∏ dT But A(x) = ∏r2 = ∏(Cx)2 So by integration: \frac{Q}{C^2x} = T + n And solving for T, I get: T(x) = \frac{Q}{C^2x} - n Which now does fit the form: T(x) = ax + b Is this correct?

So, I'm not sure if I made my point exactly clear. If I'm reading your post correctly, you're suggesting I use Fourier's Law: q"(x) = \frac{Q}{A(x)} = -k\frac{∂T}{∂x} I can obtain the information to substitute for \frac{∂T}{∂x} by differentiating T(x). My problem is not principally this...

Homework Statement Sketched below is a solid, truncated cone, with a side profile of y=Cx. Based on the geometry, the area (in m2) of the left (truncated, x = 1m) and the right face of the cone is 4∏ and 36∏, respectively. The temperature of the left face is T1=50°C and T2=30°C. Assuming...

The online homework system marks it wrong. I can't explain it. Is there another way to do this?

Homework Statement A car traveling on a flat circular track of radius 5m accelerates uniformly from rest with a tangential acceleration of 1.7m/s^2. The car makes it 0.2 of the way around the track before skidding off. Acceleration of gravity=9.8m/s^s. What is the coefficient of static...

Yeah, I see it. At first I didn't get how you identified theta, but when I sat down and looked at the geometry behind it, I figured it out. So I'm good now, right? Thanks a bunch for the help. My physics teacher is rather poor at explaining things, so this has been lifesaving.

Hmm...so why isn't mgcosѲ=Fn? I was under the impression that that was the formula for the portion of the normal force caused by gravity, and to me it seemed there was only gravity here to induce normal force...except, of course, that the centripetal force would also contribute to the normal...

So, we know then that: Fg=Fny (y-component of normal force) Fc=Fnx (x-component of normal force) From there, by way of the Pythagorean Theorem, we know: √(Fnx^2+Fny^2)=Fn Substitution: √(Fc^2+Fg^2)=Fn √([v^2m/r]^2+[mg]^2)=Fn √([v^2m/r]^2+[mg]^2)=mgcosѲ Is this logic right? If so, then...

So then, I'm not really sure where to begin. The vertical component of the normal force must equal the force of gravity, and the horizontal component must be the centripetal force. Is that correct?

Homework Statement A curve of radius 52.4 m is banked so that a car traveling with uniform speed 55 km/hr can round the curve without relying on friction to keep it from slipping to its left or right. The acceleration of gravity is 9.8 m/s2 . The mass of the car is 1800kg. What is θ...

Homework Statement Because of Earth’s rotation about its axis, a point on the Equator experiences a centripetal acceleration of 0.034 m/s2, while a point at the poles experiences no centripetal acceleration. What is the apparent weight at the equator of a person having a mass of 118.1 kg...

Homework Statement The system is in equilibrium and all pulleys are massless and frictionless. Find the tension T. The acceleration of gravity is 32 ft/s2. Note : lb = slug · ft/s2. Answer in units of lb. Homework Equations F=ma=0 The Attempt at a Solution So, I'm...