Recent content by wolfpack

Ah I see what I did now, so with the revised computation the correct solution is 2838.298 N which I checked and it works. Thank you I still have that momentum equation left for my OLI, I'm just rusty on collisions in two dimension in general. I know the resultant angles have some connection...

For the problem about impulse I have J=F (delta t)=delta p F(t)=m(v2-v1) F(4.7*10^-3)=.145(52-40) Thus F=(.145(52-40))/(4.7*10^-3)=370.213 N Apparently that is incorrect, but I am unsure of exactly what other equations to use with the quantities I have. The change in momentum I got was...

Homework Statement Problem 1: A .145 kg baseball pitched at 40 m/s is hot on a horizontal line back to the pitcher at 52 m/s. If the contact time of the ball with the bat is 4.7e-3, calculate the magnitude of the average force acting on the ball due to the bat. Problem 2:A billiard ball is...