Recent content by Wombats

The result I got for the coefficient was ## \frac{\sin^2(\frac{ \pi}{2})}{(\pi^2)} ## which is equal to 0.1013 which was the correct answer on the solution sheet.

Thank you that makes sense now.

Oops I guess I cropped it out of the image. Yeah it just tells you that the right half of the slit is covered. There were no numbers given so I just don't understand how to go about figuring it out. I think they are trying to demonstrate what changes in the pattern when you decrease the slit...

The Attempt at a Solution The solution I keep coming up with is (G) , but the solution sheet says it is (C). I assumed it was (G) because since the slit width is halved the central maximum is bigger so I assumed that X would now be part of the central maximum. Therefore the intensity would be I_0.