Recent content by woodyallen1

You can find the length of reciprocal vectors obliging them to meet with "a" point "reciprocal a" is one and with "b" point "reciprocal "b" is one. Can you explain this point a little more please?

A thought..Let a^2 +b^2-2<> 16k. a^2+b^2<>16k+2 => a^2+b^2<>2m => odd +odd<> even which is wrong. (<> different from)

16\8=0 or am i wrong?

Very Kind of you PF..

...ok?

I forgot a /2 at the second coordinate..

1 and 2 are subscripts and λ and κ scalars (numbers).

Suppose u1=(a1,(a1-c1),c1) and u2=(a2,(a2-c2),c2) i.e. each one of these fulfils the given relation, that is, it belongs to the vector space. Now uou have to prove that λu1 + κu2 belongs to vector space too. Replace u1 and u2 in the latter and you will find out that you get another vector that...

If you prove the linear combination you are ok..

Write the vector in the form (a,(c-a)/2,c). In order to form a vector space, the sum two of these must give a third of the same space(form) and a linear combination in general gives a third which belong in the same space..

Its an arbitrary equation. It could be c+5a=7b or -3c+7a+6b=0 as well. There is something missing..

f=g so f-g=0 and f/g=1...

Imagine ΔΕ as an energy loan. The shortest the process is the bigger the loan is.

Bx=102 and By=-112. Do we agree so far?

Is it helpful to imafine ΔΕ as energy fluctuation and Δt the time a process lasts?