The point of JimWhoKnew can be illustrated by the following simple analogy.
Consider an initial value problem
##\dot x^2+x^2=1,\quad x(0)=0,\quad t\ge 0.##
It has a solution ##x(t)=\sin t## for all ##t\ge 0##;
and another solution
##x(t)=\sin t## for ##t\in[0,\pi/2]## and ##x(t)=1## for...