Oh my god!
I feel terribly sorry for all of my friends. I regret for posting the wrong integral in the previous post. Especially for Ray Vickson. Thank you so much for your persistence.
Again please accept my sincere apology for giving the wrong equation.
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Best regards
Jacky Wu
Thanks for your reply.
Actually I don't know where the problem is?
But the result of f(\xi) appears in several academic papers.
I will check it later to find out which one suits better and try to find out the exact problem.
Thank you so much for all friends who replied.
I think I have worked it out, but maybe using another way to solve it.
However partial fractions really help when I solve this problem.
I needs great effort to type the integration process here, so I decide to attach the pdf
document here...
You are right. The result is displayed in post #9.
Last night I worked it out with your kind help. I would posted here later.
It would take me a little time to check.
Yeah, I see. If I strive to work it out in partial fraction, I believe the result would be messy.
However I have tried another method and it works out.
I would post here later.
But how can I use \alpha,\beta without taking its real form into consideration. Just as I put in the previous message, it has quite complicate form.
I am not very good at it, could you show me just how to use \alpha,\beta to obtain the partial fraction. Of course I will solve the integration...
I put the result f(\xi_1) here but I am not able to obtain f(\xi_1).
The question is I can't obtain f(\xi_1) from integrating f(\xi_1,\xi_2) with respect to \xi_2
I found it too difficult to obtain the partial fractions and it's hard to integrate to obtain f(\xi) in the form I put.
I got the result as follows, but I still can't work it out.
I hope if anyone could help.
f(\xi_1)=\frac{(1-\eta_1\xi_1)(1-\eta_1^2-\eta_2^2-\eta_3^2)}{2[(1-\eta_1\xi_1)^2-(\eta_2^2+\eta_3^2)(1-\xi_1^2)]^{3/2}}
where the domain of integration is -1\leq \xi_1\leq 1
I think you maybe right,not every integral can be expressed in classical functions.Maybe approximation is the only way to obtain the result.I will try to expand the integrand into series to see whether i can make a approximation.