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Thermal decomposition of calcium carbonate - problem
Should I assume that 20 g went away as CO2? So from 1 to 1 mole ratio, 0.45 moles of CaCO3 decomposed, which corresponds to 45 molecules per 100 molecules. We are left with 0.45 moles of CaO and 0.55 moles of CaCO3 which is 45 % of CaO in the final sample. Ok, the solutions agree. Thank you...- wuutoshi
- Post #5
- Forum: Biology and Chemistry Homework Help
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Thermal decomposition of calcium carbonate - problem
CaCO3 → CaO + CO2 Doesn't 20 g of the decomposed reactant corresponds to decomposition of 0.2 mole of that reactant? I don't assume that mass dissappeares. It appears as 20 g of products (0.4 moles of them). So now we are left with 0.8 moles of CaCO3, isn't that true? Ok.- wuutoshi
- Post #3
- Forum: Biology and Chemistry Homework Help
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Thermal decomposition of calcium carbonate - problem
Hello, here goes the problem: The mass of calcium carbonate upon thermal decomposition decreased by 1/5. (a) How many molecules of CaCO3 per 100 molecules were decomposed to CaO and CO2. (b) The content of CaO in the final sample express in molar fraction. My solution: I set the starting...- wuutoshi
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- Calcium Calcium carbonate Decomposition Thermal
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- Forum: Biology and Chemistry Homework Help