Recent content by xArcherx

I think it's because in a typical motor (where the rotor is the coils and the stator is the magnets) the field in the coils is being produced by the current passing through it. This field then repels the like field from the magnets. Depending on design, a motor can then be turned to produce an...

Just wanted to add to the transformer part. If you have two wires next to each other (in parallel) and have a DC through one, there will be a constant magnetic field around that one wire and the other wire will have no current/no field while sitting in the static field of the first wire. Pass...

The organ is a classic example.

Both material and design has... Improved in handling higher temperatures. Improved in strength. Improved in efficiency. Decreased in cost. Those sort of things.

Good question. The only thing that I can see causing a greater resistance on the displacement of the pump is if there exists a positive pressure at the outlet and/or a negative pressure at the inlet. Now with the opening to atmosphere, there shouldn't be a negative pressure at the inlet side...

Looks interesting, there was a lot to read so sorry if this repeats with anyone. I'm going to have a go... So you have the tube with one end open to atmosphere and the other connected to the inlet of a pump. The pump turns on and displaces, say 100cc (1m^3) of air per second. The 100cc of...

What I mean by stack is... If E = |p|c Then if we have two photons, each will have it's own momentum. So this would give us... Et = (|p| + |p|)c

That's why you should go with the full equation... E^2 = (mc^2)^2 + (pc)^2 Since m is the rest mass, you have to add the energy from the momentum, p, which (when regarding mass bearing objects) is... p = ɣmv ɣ = (1-v^2/c^2)^(-1/2) So there you get a change in momentum with a change in...

Even when you are looking for the total momentum? Where if ball 1 is 2 kg and ball 2 is 4 kg, both are traveling 10m/s then... Momentum of ball 1 is 2 * 10 = 20 Momentum of ball 2 is 4 * 10 = 40 Total momentum should be 60 kg.m/s If p means the ball is traveling from point A to point B then -p...

I can see the use of absolutes when referring to macroscopic objects of mass. Ball 1 is traveling from Point A to Point B with momentum p. Ball 2 is traveling from Point B to Point A and so it has the momentum -p in relation to Ball 1. The total momentum is... |p| + |-p| = 2p ...but talking...

Thanks, so it was the use of SI units that messed me up and I was missing the k^2 altogether. I try it again and see if my answer matches that of the site.

So it's |p| + |-p| where |-p| = |p| (of course) and so you get E = (2p)c ? Also, isn't momentum a vector?

For photons, m = 0 so E = pc. Now if you were two have a p + (-p) scenario then you get E = 0. Essentially this is two photon waves canceling each other out (destructive interference). Since p = h/λ then -p = h/-λ. p + (-p) = h/λ + h/-λ = h/λ + (-h/λ) = 0

Awesome, thanks a lot. Now I used the calculator on the sight and got a wavelength of 93.02514591068145 nm when Z = 1, n_2 = 7 and n_1 = 1. So an ultraviolet photon of ~93 nm is emitted when there is a drop from level 7 to level 1. So a question I have is where did I go wrong? Seriously...

Thanks, I'll check it out...