I also forgot to add this to the question..
The driver cannot avoid hitting the vehicle at the back of the queue. At the moment of impact, the driver's car has a remaining velocity of 15 km/hr and hits a stationary van that has a mass 1400 kg.
Assume that both vehicles are in neutral and not...
I worked out Q 1 = 15KW
By using the P= 450*(120/3.6)=15KW
But for part be i assumed the weight must be added to the equation because it states the mass of the car. Or is that figure irrelevant to work out the distance ?
Homework Statement
A car of mass 1000 kg is cruising at 120 km/hr. At this velocity the drag and friction forces that the engine needs to work against is equivalent to 450 N.
(i) What is the propulsive power being delivered by the engine when cruising? (4 marks)
(ii) From a velocity of 100...
Hi there. I am currently attempting to complete the same question. But i a stuck. Right at the start where you are working out F=PA. how did you come across the A=0.025^2..