A cone-shaped water tank is given by V(h)=\pi(h-\frac{h^2}{3}+\frac{h^3}{27})
Show using Torricelli's law law that
-2\sqrt2\pi(\frac{1}{\sqrt{h}}-\frac{2}{3}\sqrt h+\frac{1}{9}h^{3/2})\frac{dh}{dt}=1
What I have done so far:
V'=\frac{1}{9}\pi(h-3)^2h'