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xaxa
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A cone-shaped water tank is given by [tex]V(h)=\pi(h-\frac{h^2}{3}+\frac{h^3}{27})[/tex]
Show using Torricelli's law law that [tex]
-2\sqrt2\pi(\frac{1}{\sqrt{h}}-\frac{2}{3}\sqrt h+\frac{1}{9}h^{3/2})\frac{dh}{dt}=1[/tex]
What I have done so far: [tex]
V'=\frac{1}{9}\pi(h-3)^2h'[/tex]
Show using Torricelli's law law that [tex]
-2\sqrt2\pi(\frac{1}{\sqrt{h}}-\frac{2}{3}\sqrt h+\frac{1}{9}h^{3/2})\frac{dh}{dt}=1[/tex]
What I have done so far: [tex]
V'=\frac{1}{9}\pi(h-3)^2h'[/tex]