Recent content by Xioxxi

Alright, I believe I understand now. For a_{y}=a_{t}(sin\Theta), I got .77254 m/s^{2}. I believe it'd be negative too since the acceleration is going downward for that specific part, right? Then for a_{x}=a_{t}(cos\Theta) I got 2.377 m/s^{2} These feel like much better answers than what I...

I appreciate it. I'm unsure of how I would use an acceleration vector to find the other sides, though. Every other time I've done trigonometric functions prior to this I had an actual distance, which was why I was trying to find it as d at first.

Thanks for the quick reply! I thought that I was needing to use acceleration & time to find d then use sin/cos to find the other sides. How would I use an acceleration vector with the angle to find the other sides/accelerations? I'm also assuming that Ax and Ay are the non sloping part of the...

Homework Statement A skier races down an 18 degree ski slope. During a 5.0s interval, the skier accelerates at 2.5m/s squared. What are the horizontal and vertical components of the skiers acceleration during this time?Homework Equations d = ViT + 1/2aT^2 d=distance Vi=initial velocity...