Recent content by xLaser

Urea? pH level of it? Does anyone know the pH level of Urea or Sweat? I can't seem to find this info anywhere, although I think both is basic since they contain ammonia.

ok, I'm in grade 11 right now... i guess i can figure it out if they are standard for undergrad 1st years

are these programs like mathematic and maple terribly complicated to use? I'm not such an expert.

lol yeah i got to learn the things u guys use to write symbols out.

yeah dude, ... ok so u get sqrt 3 / sqrt 35 q now u multiply by sqrt 35 / sqrt 35 and u get sqrt 105 / 35 q ..... lol...

ok maybe u guys got orginial Question wrong. it's actually p = sqrt root (6 / 70q^2) so becomes sqrt 6 / sqrt 70 sqrt q^2 so becomes sqrt 6 / sqr 70 q sqrt 6 * sqrt 70 / 70q sqrt 420 / 70q sqrt 105 / 35 q

i got it its sqrt105 /35q

the question stated q is greater than 0, therefore q is pos. but how would u simplify this since q does not have a number value?

hey, just a really quick question, any help wud be great, is it possible to simplify this radical further? p = sqrt root (6/70q^2) thx in advance for help.

um guys 1 last question: can't seem to get this one properly. Q: The constant terms (this is when x ^ 0) in the expansions of (px^3 + q/x^3)^8 and (px^2 + q/x^2)^4 are equal. Both p and q are grater htan zero. Express p in terms of q. wut i did was write out the general term for both...

ok is there an example in physics where they use binomial theorm?

:: Math Computer Program? :: do you guys know if there is a computer program that can solve equations, graph stuff, expand polynomials, solve matrices etc.? thanks a lot for help.

ok collected like terms till X^3 it became 1+10x+24x^2-40x^3

Brain can't factor that... but i guess to write up to x^3 i sitll have to expand everything but for the final answre i only write terms up to x^3?

dextercioby ok i expanded the whole thing by applying the theorem several times, but it is the 2nd part of the question that is confusing me... xpand using the binomial theorm in powers of x up to and including x^3 ... i interpted this as expanding only to the point where x is cubed... but how...