Again, I'm not learning from the book, I was just self-teaching through online notes from the one i showed... and i already articulated that I grasped the idea of f(x,y,z) represent density, it's just that if it is.. then the integration usage is completely different compare to single or double...
Hi... So I've been self-teaching Calculus III and I'm currently having a hard time coping with the idea of triple integration. You know how the integrand is f(x,y,z)? isn't that the equation to represent a 4D sketch? because technically, f(x,y,z) is ANOTHER VARIABLE and therefore giving us a 4...
Okay, yes a person that agrees with me that dy/dx isn't a formal "fraction" i mean the literal translation of it is "change in y divided by change in x" but that's not it, it's just "the change in y with respect to x." because we are calculating the change infinitesimally. i heard my teacher...
Hey guys, umm I'm just going to get straight to the point, why is the notation of dy/dx for example is being abused so badly? it's not a fraction right? because you can express it in Newtonian notation like y' too! i mean it's just a notation to represent the change in y respect to x
I was...
OH! I GET IT! THANKS DUDE! still kinda not intuitive about the idea of that 15N upward force, what if the shape it different or cutting 2 shapes of different of different size?? is there a mathematical way to determine that 15N?
I can't wrap my head around this problem?
I think that when you drill a whole like that, the cylinder will roll back to attain its equilibrium so need to hold it with a certain torque to keep it in place, but i do not know how to find the torque
What i have in mind is:
since T=dL/dt, but L=Iw(w...
ok it's pretty simple, you set up 2 equations of T(air time)
so the first one is t=(vsin(theta))/g and they other one is t=x/(vcos(theta))
set them equal to each other, plug v and x in and find theta, that's it
Edit: sry, for the first one just times it by 2 so t=2(whatever is there)
ummm, i attempted it so basically i used y=1/2at^2. so imagine you're at the peak of 8.9 meters, use that equation to calculate the amount of air time before reaching the air. after that use that t to plug in the vertical kinematic equation:
y= y(knot) + v(knot)t - 1/2at^2. plug 8.9 in. For...
Ahhh I see! You can obtain the velocity of the rocket (at a certain time ofc) then use Tipler's derivation to obtain the exhausted mass velocity. Oh and the reason why I consider the exhausted mass velocity because it affects the velocity greatly IMO if you look at the derivation, same goes for...
Can you tell me more about the test stand? I thought of enforcing it horizontally and then record it frame by frame to measure how fast the flame is coming out since it's the lost mass( if I'm correct)
Hey everyone, so I'm just wondering if you guys can articulate the term "velocity of lost mass" from the rocket. After a few massaging on the equations(derivatives and integrals stuff) i found that to manipulate the thrust, one must manipulate the burn rate AND the "velocity of loss mass". all i...