Recent content by xtrmk

Could you look at this: [u(mg)]/3 = mv^2 / r I divide by 3 because it was reduced by the factor of 3 ? I canceled out the masses and: 3.266u = 441/r do I solve for the radius? Then consider a case 2 and plug it in?

Centripetal force = mv^2 / r ? But I don't have an r or m. and what do I do without a given coefficient of friction? (Sorry i just came back to class after a sick break) (edit) Am i starting it right? Fc = friction = mv^2/r u(mg) = mv^2/r?

Homework Statement A car is safely negotiating an unbanked circular turn at a speed of 21 m/s. The maximum static frictional force acts on the tires. Suddenly a wet patch in the road reduces the maximum static frictional force by a factor of three. If the car is to continue safely around the...