\frac{13(x+5) +3x(x+5)}{x-1}
Oops sorry that's what i meant! OHHHHHHHHH YAY! Thanks a lot ,i'm finally seeing the answer :biggrin: :biggrin: :biggrin: I got x is either equal to 0 or -3.8 :smile:
hmmmm, my previous equation was incorrect. Here is the correct one:
57(x+5)/(x-1) + 15x(x+5)/(x-1) +20x + 76 = 12x(x+5)/(x-1) + 44(x+5)/(x-1) + 3x + 11
Then i subtract then get:
13(\frac{x+5}{x-1}) + 3x(\frac{x+5}{x-1}) = -17x -65
=\frac{13x(x+5) +3x(x+5)}{x+1}
Any errors? :redface:
Ohhhhh ok i see :biggrin: Lol i didn't think of it that way. However I am still in a bit of a jam :confused: So I'm left with:
15x-5({x+5}/{x+1}) = 12x({x+5}/{x-1}) + 44({x+5}{x-1}) + 3x + 1
Or something like that :frown:
(4 ( \frac{x+5}{x-1} + 1 ) (3x+11)
hmm ok i think i got the hang of it :cool:
so can you tell me exactly how do i go about multiplying these two terms?
Yes, that's what i meant, but i was unsure on how to write it in that format. Well first, i tried to cross multiply but that's the problem..I'm not sure how to..
This question kinda stumped me. Can any1 post the answer with the working and all? Thanks :biggrin:
Show that
\frac{ 3 \left( \frac{x+5}{x-1} \right) + 4 }{ 4 \left( \frac{x+5}{x-1} \right) + 1 } = (3x+11)/{5x+19)
I got this problem and it just stumped me. Can anyone give me the solution? Anyways, here's the question:
Show that the average velocity of a body undergoing constant acceleration, and starting from rest. is half of its final velocity.
Thanks in advance
Yep its homework. Every Wednesday my class does a chemistry lab abd are required to write up a 'school based assesment' for the following week, so most likely i may be posting here weekly. I've got all the info needed, however, thanks for the help.
Hey, can anyone direct me to information on the role of the following metals in living systems? If you can, please state specific effects and reccomendations of importance(in the body).
Zn, Mg, Fe