so i should use Torque = -980 N (man)*1 meter (away from my pivot point of the left end of the beam) * sin(90) making it -980
and then add that with the -750N (beam) * 2meters (center of mass from the beam because it is uniform so it's l/2 or 4/2)
and that would leave T2* 4 meters because...
Homework Statement
A man is standing 1 meter in from the left of a 4 meter long beam. The beam is held up by two wires perpendicular to the beam. The beam is 750 N and the man is 100kg what are the tensions of the two wires.
Homework Equations
F = ma
Torque = F x d
The Attempt at...
I don't get what you mean by wrong component of weight, when i draw my FBD i have normal force going up and mg pointing down and
n - mg = 0 so n = mg but because its the 20 degree slope its n = mgSin20 ?
Homework Statement
a block of mass m resting on a 20° slope. The block has coefficients of friction µs = 0.80 and µk = 0.49 with the surface. It is connected via a massless string over a massless, frictionless pulley to a hanging block of mass m2 = 2.0 kg.
What is the minimum mass m that...