Is there a continuous function f(x) defined on (-\infty,+\infty) such that f(f(x))=e^{-x}?
My opinion is "no", and here is how i think:
first of all if such a function exists, it should be a "one-to-one" function, that is for every y>0, there should be exactly one x such that f(x)=y.
Thus by...