I got it. Yc=kx^2/2mg+Ya where k=5050N/m, x=.109, m=0.247kg, g=9.8m/s^2 and Ya= 0m because Ya is where the spring returns to its resting position and Yb is where the spring is compressed to 0.109m. Therefore, the maximum height above the spring the object reaches is 12.39m.
Equation was taken...
1. A block of mass 0.247 kg is placed on top of a light, vertical spring of force constant 5 050 N/m and pushed downward so that the spring is compressed by 0.109 m. After the block is released from rest, it travels upward and then leaves the spring. To what maximum height above the point of...