Hi Moxy
I think you could interpret the graph a lot simpler. As the potential energy is plottet agains the direction x, you can simply think about the whole thing as kind of a "hill" (or several "hills" in this case). If you look at the statements, it should work:
A) If you would release...
I don't have to much experience in astrophotography, but here are two pictures i would like to show you:
1. Comet 17P Holmes (1. Nov., 23:00 GMT), stack of 60 Photos with 30 seconds exposure, f=200mm SLR objective mounted on a FLI Maxcam CM7 CCD camera. The "spiral" was probably caused by a...
Hi
You already wrote down more equations than needed.
a) v=r*\omega \Rightarrow \omega=\frac{v}{r} with given velocity v (=28.8 m/s) and r (=2m) you can easily calculate the angular velocity \omega,
b) Centripetal force F_{z}=\frac{m*v^{2}}{r}=m*r*\omega^{2}
I hope this helps you a...
Hi
To prove that the 60° shot will travel 3 times as high as the 30°:
You can use the conservation of energy: Kinetic Engergy at the time of the shot equals the potential energy at the peak.
E_{kin}=E_{pot}
For E_{kin} you have to take the angle into account...
Hi Dynex
How did you try to solve it?
My approach would be:
1. Draw the situation!
2. Calculate the velocity of the mass at the end of the ramp
3. With the given friction and the velocity from 2. you should be able to get the distance the crate slides on the floor.
If this does not help...