Recent content by Yezman

I've tried every possible way to set this up that I know of and even using mathmatica I can't get the proper answer... Can someone just explain to me how to set it up (once I know the limits I can solve it) x^2 e^y bounded by z= 1-y^2 z = 0 x = 1 x = -1 I plan to set it up as a dzdydx So...

Double Integral bounded by Circle? Double integral of (2x-y)dA bounded by circle of radius 2, centered at origin I just need to figure out the limits for my integrals... I am basically lost, can someone show me how to break this up. I tried doing what I did with the previous triangle bound...

Ok... Idk what i was thinking when i had to multiply three things at a time (lack of sleep probably)Just to check... if you had (I made this up so something might be weird) ∂f/∂r = ? f(x,y,z) & x =(s,t,r) & y =(s,t,r) & z =(s,t,r) ∂f/∂r = ∂f/∂x*∂x/∂r + ∂f/∂y*∂y/∂r + ∂f/∂z*∂z/∂r ?

Is that an f prime? I am looking for ∂f/∂t I re-read the section (stewart Calc) Wouldn't it just be ∂f/∂x* ∂x/∂t + ∂f/∂y* ∂y/∂t ?

If f(x,y) = Sqrt[x^4 + y] and x = s^2 + t^2 + 1 and y = t^2 +t*Cos(2s) How do i find Partial f -------- Partial tI made the tree diagram how f depends on x and y, which both depend on s and t... so on my test I said it was (Partials of all of these)f/x*x/s*x/t + f/y*y/s*y/tLooking back now I...

Wrong area sorry. Nub here! Can someone delete this. If f(x,y) = Sqrt[x^4 + y] and x = s^2 + t^2 + 1 and y = t^2 +t*Cos(2s) How do i find Partial f -------- Partial t I made the tree diagram how f depends on x and y, which both depend on s and t... so on my test I said it...