Double Integral bounded by Circle?

[Yezman]

Double Integral bounded by Circle?

Double integral of (2x-y)dA bounded by circle of radius 2, centered at origin

I just need to figure out the limits for my integrals... I am basically lost, can someone show me how to break this up. I tried doing what I did with the previous triangle bound one (breaking it into 2) and that didn't work

 

[SammyS]

Start with the equation of the circle.

 

[HallsofIvy]

Are you to do this in Cartesian coordinates? The circle cuts the x-axis at -2 and 2 so x must range from -2 to 2. As SammyS suggested, write the equation of circle. The solve for y. You should get two values for y, corresponding to the lowest and highest values y can take on for a given x.