Recent content by yjstudent

I guess you could divide 1.5 by the time it takes to reach the end of the fall...?

I guess the v0 would be the velocity during the falling..so how fast the person is falling and the final velocity would be 0 because the person has landed.

...I have no idea...I guess you don't know v0 because you are jumping?

The answer given is -29m/s^2.

How do you solve when you don't know v0 and t? Would you still set x to 1.5?

1. You jump from the top of a boulder to the ground 1.5m below. Estimate your deceleration on landing. 2. v = v0 + at, x = x0 + v0t + 0.5at^2, v^2 = v0^2 + 2a(x-x0) 3. I initially thought that it was gravity (-9.8 m/s) but it's not the answer. I also tried making v into 0 and solving for v0...

Yay thanks I got the answer..

Opposite signs? Since v0 goes up and g goes down

The carrion goes down. I think that gravity makes it go down faster?

A California Condor is approaching its nest with a large chunk of carrion in its beak. As it approaches, it makes an upward swoop, achieving a momentary upward velocity of 12.8 m/s when the carrion falls from its mouth, hitting a cliff outcropping 32.1 m below. Determine the speed of the carrion...