Recent content by yoshiba

I think i figured it out: for destructive interference, one difference in distances is half of the wavelength. so 4-2.9=1.1 1.1=.5(lambda) 2.2=lambda then i use the equation with temperature, solve for the temperature at 20 degrees C and plug wavelength and velocity in the v=f*(lambda) equation...

so for a) I would do: 123=10*log*(P1/P0) 10^123=(P1/P0)^10 (10^123)^(1/10)=(P1/P0) is that correct?

Logarithms and Intensity---HELP ASAP! Homework Statement a)What is the intensity of sound at 123 dB? b)Compare it to that of a whisper at 20 dB. Homework Equations something with logarithms?? The Attempt at a Solution a) 10^123

Homework Statement Two loudspeakers are 2.5 m apart. A person stands 2.9 m from one speaker and 4.0 m from the other. Assume the air temperature is 20°C. a) What is the lowest frequency at which destructive interference will occur at this point? (b) Calculate the next two frequencies...

coulombs law, vectors and charge---HELP! Homework Statement Three positive particles of charges 15.0 µC are located at the corners of an equilateral triangle of side d = 16.5 cm (Fig. 16-38). Calculate the magnitude and direction of the net force on each particle. (Q1 is at the top of the...

so i would change mC to C and cm to m... F=(9*10^9)(2.7*10^-6)(12*10^-6)/(.43^2) =1.58 N is this ok?

Homework Statement What is the magnitude of the force a +12 µC charge exerts on a +2.7 mC charge 43 cm away? Homework Equations I know I have to use the equation: F=kq1q2/r^2 The Attempt at a Solution F=(9*10^9)(12)(2.7)/(43^2) =157706868.6 ?right?