hmm, first, thanks Defender! I no that u need a constant E throughout the Gaussian surface in order to extract E from the integral. but how do you explain why the E- field on Gaussian surface is affected by a charge outside of the surface?? because the ENCLOSED Q is the key right? or do u mean...
y is this statement wrong?
The electric field on a gaussian surface is generally not influenced by charge that is not enclosed by the surface.
ps: isn't the electric field proportional only to the ENCLOSED CHARGE, but not the outside charge?? :confused:
This is getting me so fRustrated
The area under both curves (velocity vs time) from t =0 to t =tf is the same. Which of the following quantities is the same from t =0 to t = tf?
A. average position B. average velocity C.average accerleration D. total displacement
E. jerk( the derivative of accerleration.
THE...