Can both average velocity and displacement be correct for constant area under v-t curve?

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yti1211
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The area under both curves (velocity vs time) from t =0 to t =tf is the same. Which of the following quantities is the same from t =0 to t = tf?

A. average position B. average velocity C.average accerleration D. total displacement
E. jerk( the derivative of accerleration.

THE correct answer is D, but I think B and D both work, because average v = total displacement/time. so is the answer key wrong?

THANKSSSSSS
 

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yti1211 said:
The area under both curves (velocity vs time) from t =0 to t =tf is the same. Which of the following quantities is the same from t =0 to t = tf?

A. average position B. average velocity C.average accerleration D. total displacement
E. jerk( the derivative of accerleration.

THE correct answer is D, but I think B and D both work, because average v = total displacement/time. so is the answer key wrong?

THANKSSSSSS

Hi yti1211! Welcome to PF! :smile:

hmm … I was going to say rubbish, you don't understand this …

but I think you're right! :biggrin:

(Unless, of course, the curves have different tfs:

D is correct even for different tfs, but B is correct only for the same tfs.)
 
haha, thanks tiny-tim! :))