hokay, so, we found that g*m=4(pi)r^3*rho.
but now we realized that our E is just C* (the condensation rate at the critical radius r*). which can't be right because that's the same equation as C... we know they aren't equal throughout the entire graph because then every g would produce an r*...
for my thermodynamics class we have a question where we need to graph the evaporation and condensation rates as functions of g, the number of g-mers in our droplet of radius r. but condensation and evaporation are given in terms of r... is there an equation to relate r and g?
i've looked...
the problem is as follows: in the ground state of the harmonic oscillator what is the probabilty of finding the particle outside the classically allowed region. where the classically allowed nrg is given by E=(1/2)m*omega^2*a^2 (where a is the amplitude).
were given that...
thats true... but there is always a flipside.
when your on the street in a big city the people around you can seem like bots, unconcerned with you until you interact with them. but just because you interact with, and feel for them doesn't nesscessarily mean that they are real due to the fact...
the assignment sheet our prof gave us, as well as our in class notes, have a plus sign between the two terms.
i'll have to bring that up with him when the next class rolls around.
so, i can get to this solution by knowing that we induce a polarization by displacing a certain number of...
i'm in a bit of a tizzy with an optics class question... it goes like this:
under the application of a time varying electric field the induced polarization in a dielectric may be described by the equation:
P = [(Ne^2)/(-m(omega)^2-im(omega)(gamma)+k)][E+(1/3(permittivity))P]
where the...