Recent content by yy112

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    Sinusoidal current phase angle question

    Homework Statement The sinusoidal current i1(t) has a phase angle of 60 degrees. Furthermore, i2(t) attains its positive peak 0.25ms earlier than the current in i2(t) (i.e i1(t) leads i2(t)). Both currents have a frequency of 500 Hz. Determine the phase angle of i2(t) Homework Equations...
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    Rms value of the half-wave rectified sinusoidal wave

    I understand that. I would get an RMS of 275. Would that be correct?
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    Rms value of the half-wave rectified sinusoidal wave

    That makes perfect sense. Now i understand it. But if i had a function such as v(t)=15+10cos(20πt) would i also apply the same equation or would i have to do something with the angular frequency?
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    Rms value of the half-wave rectified sinusoidal wave

    Vrms = sqrt ( 1/T * integral from 0-T of v^2(t) dt) Thats the equation i would use. Would it be appropriate to apply it to this question?
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    Rms value of the half-wave rectified sinusoidal wave

    The integration needs to be in a form of cos^2(x)=1/2 or 1+cos2x
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    Rms value of the half-wave rectified sinusoidal wave

    Sorry. You are correct. it is a cosine function. The question states that it is a half-wave rectified sinusoidal function. I would think that the peak value is 4. So the Vrms value is 4/2 = 2. But the question wants to see me integrate the function in some sort to get the Vrms value.
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    Rms value of the half-wave rectified sinusoidal wave

    Homework Statement I know the rms of a half wave is half the peak value. But the peak value is not given to me. Instead, the V(t) function of 4cos(20pi(x)) is given. Also the period T = 100ms Homework Equations vrms = vpeak/2 But the peak is not given! The Attempt at a Solution...
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